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A day full of math games & activities. Find one near you.

A day full of math games & activities. Find one near you.

# ∆ABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ∆ABC. Also find the length of AD.

**Solution:**

In right angled triangle BAC, AB = 5 cm, BC = 13 cm and AC = 12 cm.

Area of triangle BAC = 1/2 × Base × Height

= 1/2 × 5 cm × 12 cm

= 30 cm^{2}

Area of triangle ABC = 1/2 × Base × Height

Now BC = 13 cm

30 cm^{2 }= 1/2 × 13 cm × AD

AD = (30 cm^{2 }× 2) / 13 cm

AD = 60 cm^{2} / 13 cm

AD = 4.61 cm

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 11

**Video Solution:**

## ∆ABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also find the length of AD.

Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.2 Question 7

**Summary:**

∆ABC is right angled at A. AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm. The area of ∆ABC is 30 cm^{2}. Also 4.61 cm is the length of AD.

**☛ Related Questions:**

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- Dl And Bm Are The Heights On Sides Ab And Ad Respectively Of Parallelogram Abcd Fig 1124 If The Area Of The Parallelogram Is 1470 Cm2 Ab 35 Cm And Ad 49 Cm Find The Length

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