# By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 1; x - 1

**Solution:**

Given, the first __polynomial__ is x⁴ + 1

The second polynomial is x - 1.

We have to find the __quotient__ and the __remainder__ by actual division when the first polynomial is divided by the second polynomial.

The first polynomial can be written as x⁴ + 0x³ + 0x² + x + 1

By actual division,

Therefore, the quotient is x³ + x² + x + 1 and the remainder is 2.

**✦ Try This: **By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 2x; x - 2

Find the zeroes of the polynomial : p(x) = (x - 2)² - (x + 2)²

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 2

**NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 13**

## By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 1; x - 1

**Summary:**

By actual division, the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 1; x - 1 are x³ + x² + x + 1 and 2

**☛ Related Questions:**

- By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 2x² - 4x - . . . .
- By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 3x² + 4x + . . . .
- By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = 4x³ - 12x² + 14x . . . .

visual curriculum