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# Complete the congruence statement:

Δ BCA ≅ ? Δ QRS ≅ ?

**Solution:**

Let's consider Δ BCA and Δ BTA in the above diagram.

In Δ BCA and Δ BTA,

∠A = ∠A = 90° (given)

BC = BT (given)

BA = BA (common)

Thus, Δ BCA ≅ Δ BTA by RHS rule.

Let's consider Δ QRS and Δ QPT in the above figure.

In Δ QRS and Δ QPT,

PQ = RS (given)

∠R = ∠P (given)

QR = PT (given)

Thus, Δ QRS ≅ Δ TPQ by SAS rule.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 7

**Video Solution:**

## Complete the congruence statement:

Δ BCA ≅ ? Δ QRS ≅ ?

Class 7 Maths NCERT Solutions Chapter 7 Exercise 7.2 Question 6

**Summary:**

The complete congruence statements are Δ BCA ≅ Δ BTA and Δ QRS ≅ Δ TPQ.

**☛ Related Questions:**

- In A Squared Sheet Draw Two Triangles Of Equal Areas Such That I The Triangles Are Congruent Ii The Triangles Are Not Congruent What Can You Say About Their Perimeters
- Draw A Rough Sketch Of Two Triangles Such That They Have Five Pairs Of Congruent Parts But Still The Triangles Are Not Congruent
- If Abc And Pqr Are To Be Congruent Name One Additional Pair Of Corresponding Parts What Criterion Did You Use
- Explain Why Abc Fed

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