# Find:

(i) 2.5 × 0.3 (ii) 0.1 × 51.7 (iii) 0.2 × 316.8

(iv) 1.3 × 3.1 (v) 0.5 × 0.05 (vi) 11.2 × 0.15 (vii) 1.07 × 0.02

(viii) 10.05 × 1.05 (ix) 101.01 × 0.01 (x) 100.01 × 1.1

**Solution:**

We will use the concepts of decimals and fractions to solve the given questions.

(i) 2.5 × 0.3

= 25/10 × 3/10

= 25 × 3/100

= 75/100

= 0.75

(ii) 0.1 × 51.7

= 1/10 × 517/10

= 1 × 517/100

= 517/100

= 5.17

(iii) 0.2 × 316.8

= 2/10 × 3168/10

= 2 × 3168/100

= 6336/100

= 63.36

(iv) 1.3 × 3.1

= 13/10 × 31/10

= 13 × 31/100

= 403/100 = 4.03

(v) 0.5 × 0.05

= 5/10 × 5/100

= 5 × 5/1000

= 25/1000

= 0.025

(vi) 11.2 × 0.15

= 112/10 × 15/100

= 112 × 15/1000

= 1680/1000

= 1.68

(vii) 1.07 × 0.02

= 107/100 × 2/100

= 107 × 2/10000

= 214/10000

= 0.0214

(viii) 10.05 × 1.05

= 1005/100 × 105/100

= 1005 × 105/10000

= 105525/10000

= 10.5525

(ix) 101.01 × 0.01

= 10101/100 × 1/100

= 10101 × 1/10000

= 10101/10000

= 1.0101

(x) 100.01 × 1.1

= 10001/100 × 11/10

= 10001 × 11/1000

= 110011/1000

= 110.011

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 2

**Video Solution:**

## Find: (i) 2.5 × 0.3 (ii) 0.1 × 51.7 (iii) 0.2 × 316.8 (iv) 1.3 × 3.1 (v) 0.5 × 0.05 (vi) 11.2 × 0.15 (vii) 1.07 × 0.02 (viii) 10.05 × 1.05 (ix) 101.01 × 0.01 (x) 100.01 × 1.1

NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.6 Question 5

**Summary:**

The value of the following : (i) 2.5 × 0.3 (ii) 0.1 × 51.7 (iii) 0.2 × 316.8 (iv) 1.3 × 3.1 (v) 0.5 × 0.05 (vi) 11.2 × 0.15 (vii) 1.07 × 0.02 (viii) 10.05 × 1.05 (ix) 101.01 × 0.01 (x) 100.01 × 1.1 are (i) 0.75, (ii) 5.17 , (iii) 63.36, (iv) 4.03 , (v) 0.025, (vi) 1.68 , (vii) 0.0214, (viii) 10.5525 , (ix) 1.0101 and (x) 110.011 respectively.

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