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# Find the perimeter of each of the following shapes: (a) A triangle of sides 3 cm, 4 cm and 5 cm (b) An equilateral triangle of side 9 cm (c) An isosceles triangle with equal sides 8 cm each and third side 6 cm

**Solution:**

We will be using the formula of the perimeter of a triangle which is equal to the sum of all sides of a triangle

Hence,

(a) Perimeter of triangle = Sum of all three sides

Therefore, the triangle's perimeter = 3 + 4 + 5 = 12 cm

Hence, the perimeter of the triangle is 12 cm

(b) An equilateral triangle's perimeter = 3 x side [Since all the sides are equal]

Thus, perimeter of the triangle = 3 × 9 = 27 cm

Therefore, 27 cm is the perimeter of an equilateral triangle

(c) An isosceles triangle's perimeter = Sum of all its sides

Thus, perimeter of the triangle = 8 + 8 + 6 = 22 cm

Therefore, 22 cm is the perimeter of an isosceles triangle.

NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.1 Question 6

## Find the perimeter of each of the following shapes: (a) A triangle of sides 3 cm, 4 cm and 5 cm (b) An equilateral triangle of side 9 cm (c) An isosceles triangle with equal sides 8 cm each and third side 6 cm.

**Summary:**

The perimeter of each of the given shapes is 12 cm, 27 cm and 22 cm respectively.

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