Find the values of the letters in the following and give reasons for the steps involved.
Each letter in the given puzzle must stand for just one digit.
The operation performed here is multiplication.
- The multiplication of 3 and B gives a number whose one’s digit is B again. Hence, B must be 0 or 5.
- Let B be 5. Multiplication of the first step = 3 × 5 = 15, 1 will be a carry for the next step. We have, 3 × A + 1 = CA. This is not possible for any value of A.
- Hence, B must be 0 only. If B = 0, then there will be no carry for the next step. We should obtain, 3 × A = CA That is, the one’s digit of 3 × A should be A. This is possible when A = 5 or 0.
- However, A cannot be 0 as AB is a two-digit number. Therefore, A must be 5 only.
The multiplication is as follows.
Hence, the values of A, B, and C are 5, 0, and 1 respectively.
Find the values of the letters in the following and give reasons for the steps involved. AB × 3 = CAB
Class 8 Maths NCERT Solutions - Chapter 16 Exercise 16.1 Question 5
The values of the letters A, B, and C are 5, 0, and 1 respectively.