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# If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.

**Solution:**

Given: Linear equation 3y = ax + 7.

We can find the value of 'a' by substituting the values of x and y in the given equation

By substituting the value of x = 3 and y = 4 in the the equation 3y = ax + 7, we get

3(4) = a(3) + 7

12 = 3a + 7

3a = 5

a = 5/3

Hence, the value a = 5/3

**☛ Check: **NCERT Solutions Class 9 Maths Chapter 4

**Video Solution:**

## If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.

NCERT Solutions Class 9 Maths Chapter 4 Exercise 4.3 Question 3

**Summary:**

If the point (3, 4) lies on the graph of the equation 3y = ax +7, then the value of a = 5/3.

**☛ Related Questions:**

- Draw the graph of each of the following linear equations in two variables: (i) x + y = 4 (ii) x - y = 2 (iii) y = 3x (iv) 3 = 2x + y
- Give the equations of two lines passing through (2, 14). How many more such lines are there, and why?
- The taxi fare in a city is as follows: For the first kilometre, the fare is ₹ 8 and for the subsequent distance it is ₹ 5 per km. Taking the distance covered as x km and total fare as ₹ y, write a linear equation for this information, and draw its graph.
- From the choices given below, choose the equation whose graphs are given in Fig. 4.6 and Fig. 4.7. For fig. 4.6 (i) y = x (ii) x + y = 0 (iii) y = 2x (iv) 2 + 3y = 7x For fig. 4.7 (i) y = x + 2 (ii) y = x - 2 (iii) y = -x + 2 (iv) x + 2y = 6.

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