# Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

**Solution:**

Let's construct a diagram according to the given conditions.

Visually area of given figure (trapezium) is sum of the area of two triangles.

Length of the fence of a trapezium shaped field ABCD = AB + BC + CD + AD

120 m = AB + 48 m + 17 m + 40 m

120 m = AB + 105 m

AB = 120 m − 105 m = 15 m

Area of the field ABCD = 1/2 × [Length of the parallel side] × [Distance between two parallel sides]

= 1/2 × (AD + BC) × AB

= 1/2 × (40 + 48) × 15 m

= 1/2 × (88 m) × 15 m

= 44 m × 15 m

= 660 m²

Thus, area of the field ABCD is 660 m²

**Video Solution:**

## Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC

### Class 8 Maths NCERT Solutions - Chapter 11 Exercise 11.2 Question 3

**Summary:**

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, the area of the field ABCD is 660 m² and AB is 15 m.