# Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times

**Solution:**

We will use the concept of the HCF(Highest Common Factor) to solve this.

To determine the maximum capacity of a container that can measure the diesel of the three containers an exact number of times, we need to calculate the HCF of 403, 434 and 465.

So, prime factorization of 403, 434 and 465 are as follows,

403 = 13 × 31

434 = 2 × 7 × 31

465 = 3 × 5 × 31

Here we observe that 31 is the highest common factor of 403, 434 and 465.

Therefore, the maximum capacity of the required container that can measure the diesel of the three containers an exact number of times will be 31 litres.

You can also use the HCF Calculator to answer this.

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.7 Question 7

## Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

**Summary:**

If three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively, the maximum capacity of the required container that can measure the diesel of the three containers an exact number of times will be 31 litres.

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