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# Find the equation of a line passing through the points (-1,1) and (2,-4).

The general equation of a straight line can be written as y = mx + c where m is the slope and c is the y-intercept.

## Answer: The equation of a line passing through the points (-1, 1) and (2, -4) is 5x + 3y + 2 = 0.

Let us proceed step by step

**Explanation:**

Let us consider the given points (-1, 1) and (2, -4).

As we know that the equation of a line passing through the points ( x_{1 , }y_{1}) and ( x_{2} , y_{2}) is given by y - y_{1} = m ( x - x_{1}).

Where m is the slope given by the formula m = (y_{2} - y_{1}) / (x_{2} - x_{1})

You can find the slope using Cuemath's Slope Calculator.

Hence on substituting the given points in the equation of a line, we get

y - 1 = m ( x - (-1) ) -------(1)

m = (y_{2} - y_{1}) / (x_{2} - x_{1})

m = (-4 - 1) / (2 - (-1))

m = -5 / 3

Substituting value of m in equation (1), we get

y - 1 = -5 / 3 (x + 1)

3y - 3 = -5 (x + 1)

5x + 3y + 2 = 0

### Therefore, the equation of a line passing through the points (-1, 1) and (2, -4) is 5x + 3y + 2 = 0.

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