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# Find the roots of f(x) = (x - 6)^{2 }(x + 2)^{2}

The roots of any function f(x) are the values of x for which the value of the function f(x) = 0.

## Answer: The roots of f(x) = (x - 6)^{2}(x + 2)^{2} are x = 6 and x = -2

Let us proceed step by step to find the roots of f(x).

**Explanation: **

Let us consider the given function, f(x) = (x - 6)^{2 }(x + 2)^{2}

As we know that roots are the values of x for which the value of function must be equal to zero.

Therefore, f(x) must be equal to zero.

⇒ (x - 6)^{2 }(x + 2)^{2} = 0

⇒ (x - 6)^{2} = 0 or (x + 2)^{2} = 0 [ since product of both expressions is zero ]

⇒ x = 6 or x = -2 [ on simplifying the above equation ]

### Hence, the roots of f(x) = (x - 6)^{2 }(x + 2)^{2} are x = 6 and x = -2

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