Volume of a Right Square Pyramid
The volume of a right square pyramid is the space occupied by the right square pyramid. A right square pyramid is a threedimensional geometric shape that has a right square base and four triangular faces that are joined at a vertex. Let's learn how to find the volume of a right square pyramid with the help of a few solved examples and practice questions. Stay tuned for more!!!
1.  What is Volume of a Right Square Pyramid? 
2.  Formula of Volume of a Right Square Pyramid 
3.  How to Find the Volume of a Right Square Pyramid? 
4.  FAQs on Right Square Pyramid Volume 
What is Volume of a Right Square Pyramid?
The volume of a right square pyramid is the number of unit cubes that can fit into it. A right square pyramid is a threedimensional shape that has a right square base and four triangular faces that are joined at a vertex. A right square pyramid is a polyhedron (pentahedron) with five faces. The unit of volume is "cubic units". For example, it can be expressed as m^{3}, cm^{3}, in^{3}, etc depending upon the given units.
A right square pyramid has three components.
 The top point of the pyramid is called the apex.
 The bottom right square is called the base.
 The triangular sides are called faces.
Formula of Volume of a Right Square Pyramid
The formula to determine the volume of a right square pyramid is V = 1/3 × b^{2} × h where "b" is the length of the base and "h" is the perpendicular height. The relation between slant height, perpendicular height, and the base is given by using Pythagoras Theorem s^{2} = h^{2} + (b/2)^{2} where "s", "h" and "b" are slant height, the height of perpendicular, and base length of the right square pyramid. Thus, the volume of the right square pyramid is given by replacing the given dimensions in the formula V = 1/3 × b^{2} × h.
How to Find the Volume of a Right Square Pyramid?
As we learned in the previous section, the volume of a right square pyramid could be found using \(\dfrac{1}{3} \times \text{b}^2 \times \text{h}\). Thus, we follow the below steps to find the volume of a right square pyramid.
 Step 1: Determine the base area (b^{2}) and the height (h) of the pyramid.
 Step 2: Find the volume using the formula 1/3 × b^{2} × h
 Step 3: Represent the final answer with cubic units.
Example: Find the value of the right square pyramid having height and length of the base edge of 9 units and 5 units respectively.
Solution: Given that h = 9 units and b = 5 units.
Then, the volume of the right square pyramid is V = 1/3 × b^{2} × h
⇒ V = 1/3 × 5^{2} × 9
⇒ V = 5^{2} × 3 = 75 cubic units
The volume of the right square pyramid is 75 cubic units.
Solved Examples on Volume of a Right Square Pyramid

Example 1: Julia has a vessel in the form of an inverted regular right square pyramid that has to be filled with water. The altitude of the vessel is 10 inches and the length of the base edge is 7 inches. What is the volume of water Julia can fill in the vessel?
Solution: Given h = 10 inches and b = 7 inches
The volume of the vessel is given by V = 1/3 × b^{2} × h
⇒ V = 1/3 × 7^{2} × 10
⇒ V = 490/3
⇒ V = 163.33 cubic inches
Thus, the volume of the vessel is 163.33 in^{3}. 
Example 2: What will be the volume of a regular square pyramid with base sides 10 cm and a height of 18 cm?
Solution: Given that b = 10 cm and h = 18 cm
The formula for the volume of a pyramid is given by V = 1/3 × b^{2} × h
The area of the base = The square of base length = 10^{2} or 100 cm^{2}.
Putting the values B = 100 and h = 18 in the formula.V = 1/3 × 100 × 18 = 600 cm^{3}.
Answer: The volume of the given right square pyramid is 600 cm^{3}.
FAQs on Volume of a Right Square Pyramid
What is the Volume of a Right Square Pyramid?
The volume of a right square pyramid is defined as the number of unit cubes that can fit into a right square pyramid. A right square pyramid is a threedimensional geometric shape that has a right square base and four triangular faces that are joined at a vertex.
What Units Are Used With the Volume of the Right Square Pyramid?
The unit used with the volume of the right square pyramid is given in cubic units. For example, m^{3}, cm^{3}, in^{3}, etc depending upon the given units.
What is the Formula of the Volume of the Right Square Pyramid?
The formula of the volume of the right square pyramid is given as V = 1/3 × Base Area × Height = 1/3 × b^{2} × h where b^{2} shows the base area and h shows the height of the right square pyramid.
How to Find the Volume of a Right Square Pyramid?
The volume (V) of a right square pyramid can be found by using the following steps:
 Step 1: Find the base area (b^{2}) and the height (h) of the pyramid.
 Step 2: Determine the volume using the formula 1/3 × b^{2} × h
 Step 3: Now, write the final answer with cubic units.
How to Find the Volume of a Right Square Pyramid with Slant Height?
The volume (V) of a right square pyramid can be found by using the following steps:
 Step 1: Identify the given dimensions of the right square pyramid.
 Step 2: Find the missing dimension using the formula s^{2} = h^{2} + (b/2)^{2} where "s", "h", and "b" are slant height, the height of perpendicular, and base length of the right square pyramid.
 Step 2: Determine the volume using the formula 1/3 × b^{2} × h
 Step 3: Now, write the final answer with cubic units.
What Happens to the Volume of a Right Square Pyramid If the Height of the Pyramid is Doubled?
The volume of the right square pyramid is doubled if the height of the pyramid is doubled as "h" in the formula is substituted as V = 1/3 × b^{2} × h = 1/3 × b^{2} × (2h) = 2 × (1/3 × b^{2} × h) which gives double the volume of the original volume of the right square pyramid.
What Happens to the Volume of a Right Square Pyramid If the Base Area of the Pyramid is Halved?
The volume of the right square pyramid becomes one fourth the original volume if the base area of the pyramid is halved as "b/2" in the formula is substituted as V = 1/3 × b^{2} × h = 1/3 × (b/2)^{2} × h = (1/4) × (1/3 × b^{2} × h) which gives one fourth the volume of the original volume of the right square pyramid.