# Multiply the following fractions:

i) 2/5 × \(5\tfrac{1}{4}\) ii) \(6\tfrac{2}{5}\) × 7/9 iii) 3/2 × \(5\tfrac{1}{3}\)

iv) 5/6 × \(2\tfrac{3}{7}\) v) \(3\tfrac{2}{5}\) × 4/7 vi) \(2\tfrac{3}{5}\) × 3

vii) \(3\tfrac{4}{7}\) × 3/5

**Solution:**

A fraction is an equal part of the whole thing. We can find the product of two or more fractions by multiplying the numerator with numerator and denominator with denominator.

i) 2/5 × \(5\tfrac{1}{4}\)

By converting the mixed fraction into an improper fraction, and then multiplying it we get,

= 2/5 × 21/4

= 42/20

Reducing to the lowest form, we get 42/ 20 = 21/10 (improper fraction)

Converting into mixed fraction, we get \(2\tfrac{1}{10}\)

ii) \(6\tfrac{2}{5}\) × 7/9 = 32/5 × 7/9

= 224/45 (improper fraction)

Converting 224/45 into mixed fraction, we get \(4\tfrac{44}{45}\)

iii) 3/2 × \(5\tfrac{1}{3}\)

= 3/2 × 16/3

= 48/6

Reducing to the lowest term, we get 8

iv) 5/6 × \(2\tfrac{3}{7}\)

= 5/6 × 17/7

= 85/42

Reducing to the lowest term, we get \(2\tfrac{1}{42}\)

v) \(3\tfrac{2}{5}\) × 4/7

= 17/5 × 4/7

= 68/35 (improper fraction)

Converting 68/35 into mixed fraction, we get \(1\tfrac{33}{35}\)

vi) \(2\tfrac{3}{5}\) × 3

= 13/5 × 3

= 39/5 (improper fraction)

Converting 39/5 into a mixed fraction, we get \(7\tfrac{4}{5}\)

vii) \(3\tfrac{4}{7}\) ×3/5 = 25/7 × 3/5

= 75/35 (improper fraction)

Reducing 75/35 to the lowest term we get 15/7 (improper fraction)

Converting 15/7 into a mixed fraction, we get \(2\tfrac{1}{7}\)

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 2

**Video Solution:**

## Multiply the following fractions: i) 2/5 × \(5\tfrac{1}{4}\) ii) \(6\tfrac{2}{5}\) × 7/9 iii) 3/2 × \(5\tfrac{1}{3}\) iv) 5/6 × \(2\tfrac{3}{7}\) v) \(3\tfrac{2}{5}\) × 4/7 vi) \(2\tfrac{3}{5}\) × 3 vii) \(3\tfrac{4}{7}\) × 3/5

NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.3 Question 3

**Summary:**

The value of the product of fractions i) 2/5 × \(5\tfrac{1}{4}\) ii) \(6\tfrac{2}{5}\) × 7/9 iii) 3/2 × \(5\tfrac{1}{3}\) iv) 5/6 × \(2\tfrac{3}{7}\) v) \(3\tfrac{2}{5}\) × 4/7 vi) \(2\tfrac{3}{5}\) × 3 vii) \(3\tfrac{4}{7}\) × 3/5 are i) 21/10 = \(2\tfrac{1}{10}\), ii) 224/45 = \(4\tfrac{44}{45}\) iii) 8 iv) 85/42 = \(2\tfrac{1}{42}\) v) 68/35 = \(1\tfrac{33}{35}\) vi) 39/5 = \(7\tfrac{4}{5}\) and vii) 15/7 = \(2\tfrac{1}{7}\)

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