# Tick the correct answer in the following:

Area of a sector of angle p (in degrees) of a circle with radius R is

(A) p/180° × 2πR

(B) p/180° × 2πR^{2}

(C) p/360° × 2πR

(D) p/720° × 2πR^{2}

**Solution:**

We use the concept of the area of sectors of a circle to solve the problem.

Consider, area of the sector of angle θ = θ/360° × πr², where r is the radius of the circle

Here, θ = p and r = R

Substituting the above values in the formula, we get the area of the sector = p/360° × πr^{2}

Multiplying numerator and denominator of formulas obtained above by 2, we get

Area of the sector = p/720° × 2πR^{2}

Let the radius of a circle be R

We know, area of a sector of angle θ = θ/360° × πR^{2}

∴ Area of a sector of angle p = p/360° × πR^{2}

Thus, multiplying and dividing by 2,

= 1/2 (p/360° × 2πR^{2})

= p/720° × 2πR^{2}

Hence, D is the correct answer.

**Video Solution:**

## Tick the correct answer in the following: Area of a sector of angle p (in degrees) of a circle with radius R is (A) p/180° × 2πR (B) p/180° × 2πR^{2 }(C) p/360° × 2πR (D) p/720° × 2πR^{2}

### NCERT Solutions Class 10 Maths - Chapter 12 Exercise 12.2 Question 14

Tick the correct answer in the following: Area of a sector of angle p (in degrees) of a circle with radius R is (A) p/180° × 2πR (B) p/180° × 2πR2 (C) p/360° × 2πR (D) p/720° × 2πR^{2}

The area of a sector of angle p (in degrees) of a circle with radius R is (P/720°) × 2πR^{2}.