# Tick the correct answer in the following:

Area of a sector of angle p (in degrees) of a circle with radius R is

(A) p/180 × 2πR

(B) p/180 × 2πR^{2}

(C) p/360 × 2πR

(D) p/720 × 2πR^{2}

**Solution:**

We use the concept of the area of sectors of a circle to solve the problem.

Consider, area of the sector of angle θ = θ/360° × πr², where r is the radius of the circle

Here, θ = p and r = R

Substituting the above values in the formula, we get the area of the sector = p/360° × πR^{2}

Multiplying numerator and denominator of p/360° × πR^{2 }by 2, we get

Area of the sector = p/720° × 2πR^{2}

Hence, D is the correct answer.

**☛ Check: **NCERT Solutions Class 10 Maths Chapter 12

**Video Solution:**

## Tick the correct answer in the following: Area of a sector of angle p (in degrees) of a circle with radius R is (A) p/180 × 2πR (B) p/180 × 2πR^{2 }(C) p/360 × 2πR (D) p/720 × 2πR^{2}

NCERT Solutions Class 10 Maths Chapter 12 Exercise 12.2 Question 14

**Summary:**

The area of a sector of angle p (in degrees) of a circle with radius R is (p/720°) × 2πR^{2 }which is option (D).

**☛ Related Questions:**

- Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.
- Find the area of a quadrant of a circle whose circumference is 22 cm.
- The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.
- A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding : (i) minor segment (ii) major sector. (Use π = 3.14)

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