# Find an equation of the line passing through the points (2, 3) and (4, 6).

The general equation of a straight line can be written as y = mx + c where m is the slope and c is the y-intercept.

## Answer: The equation of a line passing through the points (2, 3) and (4, 6) is 3x - 2y = 0

Let us proceed step by step to find the equation of the line.

**Explanation:**

Let us consider the given points (2, 3) and (4, 6).

As we know that the equation of a line passing through the points (x_{1},_{ }y_{1}) and (x_{2}, y_{2}) is given by y - y_{1} = m (x - x_{1}).

Here, m is the slope given by the formula m = (y_{2} - y_{1}) / (x_{2} - x_{1})

Try using Cuemath's Slope Calculator that helps you to calculate the slope in a few seconds.

Hence on substituting the given points in the equation of a line, we get

y - 3 = m (x - 2)

m = (y_{2} - y_{1}) / (x_{2} - x_{1})

m = (6 - 3) / (4 - 2)

m = 3 / 2

Substituting value of m in y - 3 = m (x - 2), we get

⇒ y - 3 = 3 / 2 ( x - 2 )

⇒ 2y - 6 = 3x - 6

⇒ 2y - 3x = 0

⇒ 3x - 2y = 0

You can use Cuemath's online Equation of Line calculator to find the equation of line.

### Therefore, the equation of a line passing through the points (2, 3) and (4, 6) is 3x - 2y = 0

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