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# A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall

**Solution:**

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

AB is the height of the window from the ground = 8m

AC is the length of the ladder = 10m

BC is the foot of the ladder from the base of the ground = ?

Since ΔABC is right angled triangle (∠ABC = 90°)

Using Pythagoras theorem,

BC^{2} = AC^{2} - AB^{2}

BC^{2} = 10^{2} - 8^{2}

BC^{2} = 100 - 64

BC^{2} = 36

BC = 6

The distance of the foot of the ladder from the base of the wall is 6 m.

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 6

**Video Solution:**

## A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.

NCERT Class 10 Maths Solutions Chapter 6 Exercise 6.5 Question 9

**Summary:**

If a ladder 10 m long reaches a window 8 m above the ground, then the distance of the foot of the ladder from the base of the wall is 6 m.

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