# A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall

**Solution:**

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. [Pythagoras theorem]

AB is the height of the window from the ground = 8m

AC is the length of the ladder = 10m

BC is the foot of the ladder from the base of the ground =?

Since ΔABC is right angled triangle (∠ABC = 90°)

BC^{2} = AC^{2} - AB^{2} (Pythagoras theorem)

BC^{2} = 10^{2} - 8^{2}

BC^{2} = 100 - 64

BC^{2} = 36

BC = 6 m

The distance of the foot of the ladder from the base of the wall is 6m.

**Video Solution:**

## A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall

### NCERT Class 10 Maths Solutions - Chapter 6 Exercise 6.5 Question 9:

A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall

A ladder 10 m long reaches a window 8 m above the ground. Then the distance of the foot of the ladder from the base of the wall is 6m