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# Insert a rational number and an irrational number between 3.623623 and 0.484848

**Solution:**

Given, the numbers are 3.623623 and 0.484848.

Rational numbers are numbers which are in the form of p/q, where q is not equal to 0, p and q are integers.

Irrational numbers are numbers which are in decimal form.

To find a rational number R, we use the formula,

R = (p + q)/2

Let p = 3.623623 and q = 0.484848, we get,

R = (3.623623 + 0.484848)/2

R = (4.108471)/2

R = 2.0542355.

To find an irrational number Q, we use the formula,

Q = √pq,

where p and q are not perfect squares.

Q = √3.623623(0.484848)

Q = 1.3254834455….

Therefore, the rational number is 2.0542355 and the irrational number is 1.3254834455

**✦ Try This: **Insert a rational number and an irrational number between 2.676767 and 3.090909.

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 1

**NCERT Exemplar Class 9 Maths Exercise 1.3 Problem 3(ix)**

## Insert a rational number and an irrational number between 3.623623 and 0.484848

**Summary:**

The rational number and irrational number between 3.623623 and 0.484848 are 2.0542355 and 1.3254834455… respectively

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