# S and T are points on sides PR and QR of ∆PQR such that ∠P = ∠RTS. Show that ΔRPQ ~ ΔRTS.

**Solution:**

Let's draw ∆PQR as per the given question.

If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.

This is referred to as the AA similarity criterion for two triangles.

In ΔRPQ and ΔRTS,

∠RPQ = ∠RTS (given)

∠PRQ = ∠TRS (common angle)

Thus, ΔRPQ ∼ ΔRTS (AA criterion)

**Video Solution:**

## S and T are points on sides PR and QR of ∆PQR such that ∠P = ∠RTS. Show that ΔRPQ ~ ΔRTS.

### NCERT Class 10 Maths Solutions - Chapter 6 Exercise 6.3 Question 5:

**Summary:**

If S and T are points on sides PR and QR of ∆PQR such that ∠P = ∠RTS, we proved that ΔRPQ ~ ΔRTS using AA criteria.