Integration of UV Formula
Integration of uv formula is a convenient means of finding the integration of the product of the two functions u and v. Further, the two functions used in this integration of uv formula can be algebraic expressions, trigonometric ratios, or logarithmic functions. We expand the differential of a product of functions and express the given integral in terms of a known integral. Thus integration of uv formula is also known as integration by parts or the product rule of integration. Let's learn the integration of uv formula and its applications.
What is Integration of UV Formula?
The integration of uv formula is a special rule of integration by parts. Here we integrate the product of two functions. If u(x) and v(x) are the two functions and are of the form ∫u dv, then the Integration of uv formula is given as:
- ∫ uv dx = u ∫ v dx - ∫ (u' ∫ v dx) dx
- ∫ u dv = uv - ∫ v du
where,
- u = function of u(x)
- dv = variable dv
- v = function of v(x)
- du = variable du
Integration of UV Formula
We follow the following simple quick steps to find the integral of the product of two functions:
- Identify the function u(x) and v(x). Choose u(x) using the LIATE rule: whichever first comes in this order: Logarithmic, Inverse, Algebraic, Trigonometric, or Exponential function.
- Find the derivative of u: du/dx
- Integrate v: ∫v dx
- Key in the values in the formula ∫u.v dx = u. ∫v.dx- ∫( ∫v.dx.u'). dx
- Simplify and solve.
Derivation of Integration of UV Formula
We will derive the integration of uv formula using the product rule of differentiation. Let us consider two functions u and v, such that y = uv. On applying the product rule of differentiation, we will get,
d/dx (uv) = u (dv/dx) + v (du/dx)
Rearranging the terms, we have,
u (dv/dx) = d/dx (uv) - v (du/dx)
Integrate on both the sides with respect to x,
∫ u (dv/dx) (dx) = ∫ d/dx (uv) dx - ∫ v (du/dx) dx
⇒ ∫u dv = uv - ∫v du
Hence, the integration of uv formula is derived.
Let us try out a few examples to better understand how to apply the integration of uv formula.
Solved Examples Using Integration of UV Formula
Example 1:Find the integral of x.Sinx.
Solution:
Here u = x and dv = sin x dx
du = dx and v = ∫sinx dx= - cos x dx
Using the uv formula ∫u.dv = uv- ∫v du we get
∫x sinx dx = x. (-cos x) - ∫(-cos x dx)
= -x cos x - (-sin x) + C
= -x cos x + sin x + C
Answer: ∫x.sinx.dx = sin x - x cos x + C
Example 2: Find the integral of x2.logx
Solution:
Here u = logx and dv = x2 dx
du = 1/x dx and v = x3 /3 + C
Using the integration of uv formula ∫u.dv = uv- ∫v du we get
∫x2 log x dx= log x. (x 3/3) - ∫(x3/3)(1/x)dx
= log x. (x 3/3) -(1/3) ∫(x3)(1/x)dx
= log x. (x 3/3) -(1/3) ∫x2dx
= (x3/3)log x - (1/3) (x3 /3)+C
=(x3/3) log x- (x3/9)+ C
Answer: ∫x2logx = (x3/3) log x- (x3/9)+ C
Example 3: Find the integral of xex dx.
Solution:
Here u = x and dv = exdx.
du = dx and v = ex
Using the integration of uv formula ∫u.dv = uv- ∫v du, we get
∫xex dx = x ex - ∫ ex dx
= xex - ex + C
Answer: Thus integral of xex dx= xex - ex +C
FAQs on Integration of UV Formula
What is the Formula of Integration of UV?
The formula of integration of uv is ∫u.v = u. ∫v.dx- ∫( ∫v.dx.u'). dx. The formula of integration of uv helps us evaluate the integrals of product of two functions.
How do You Use the Formula of Integration of UV?
Identify the integral of the form ∫u.vdx. Choose u(x) using the LIATE rule and differentiate it. Choose v(x) and Integrate dv. Then plug in all the values obtained so far, in the formula ∫u.v = u. ∫v.dx- ∫( ∫v.dx.u'). dx and evaluate the integral.
What Does DV mean in Integration of uv Formula?
When the integral is of the form ∫u.vdx, we need to apply the formula of integration of uv. Use the LIATE rule and identify the function u(x). The other function is v(x) and it is of the form dv. We integrate dv to get v.
What is Meant by Integration By Parts?
Integration by parts is a technique used as the formula of integration of uv to integrate a definite or an indefinite integral which is as a product of two functions. We expand the differential of the product of the functions and express the original integral in terms of a known integral as ∫u.v = u. ∫v.dx- ∫( ∫v.dx.u'). dx
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