Derivatives
A derivative in calculus is the rate of change of a quantity y with respect to another quantity x. It is also termed the differential coefficient of y with respect to x. Differentiation is the process of finding the derivative of a function.
Let us learn what exactly a derivative means in calculus and how to find it along with rules and examples.
Meaning of Derivatives in Calculus
The derivative of a function f(x) is usually represented by d/dx (f(x)) (or) df/dx (or) Df(x) (or) f'(x). Let us see what a derivative technically means. Consider a curve of function f(x) and let two points on it be (x, f(x)) and ((x + h), f(x + h)). Then the slope of the secant line through these points is given by [f(x + h)  f(x)]/(x + h  x) = [f(x + h)  f(x) / h. See the figure below and observe that when the distance between two points is closely equal to 0 (i.e., as h approaches 0), the second point overlaps the original point and the secant line becomes the tangent line. In calculus, the slope of the tangent line is referred to as the derivative of the function. i.e.,
 The derivative of the function, f '(x) = Slope of the tangent = lim_{h→0 }[f(x + h)  f(x) / h.
This formula is popularly known as the "limit definition of the derivative" (or) "derivative by using the first principle".
Interpretation of Derivatives
The derivative of a function f(x) in math is denoted by f'(x) and can be contextually interpreted as follows:
 The derivative of a function at a point is the slope of the tangent drawn to that curve at that point.
 It also represents the instantaneous rate of change at a point on the function.
 The velocity of a particle is found by finding the derivative of the displacement function.
 The derivatives are used to optimize (maximize/minimize) a function.
 They are also used to find the intervals where the function is increasing/decreasing as well as the intervals where the function is concave up/down.
Thus, whenever we see the phrases like "slope/gradient", "rate of change", "velocity (given the displacement)", "maximize/minimize" etc then it means that the concept of derivatives is involved.
Derivative of a Function Using the First Principle
The derivative of a function can be obtained by the limit definition of derivative which is f'(x) = lim_{h→0 }[f(x + h)  f(x) / h. This process is known as the differentiation by the first principle. Let f(x) = x^{2 }and we will find its derivative using the above derivative formula. Here, f(x + h) = (x + h)^{2} as we have f(x) = x^{2}. Then the derivative of f(x) is,
f '(x) = lim_{h→0 }[(x + h)^{2}  x^{2}] / h
= lim_{h→0 }[ x^{2} + 2xh + h^{2}  x^{2}] / h
= lim_{h→0 }[ 2xh + h^{2}] / h
= lim_{h→0 }[ h(2x + h) ] / h
= lim_{h→0 }(2x + h)
= 2x + 0
= 2x
Thus, the derivative of x^{2} is 2x. But it may be difficult to use this limit definition to find the derivatives of complex functions. Thus, there are some derivative formulas (of course, which are derived from the above limit definition) that we can use readily in the process of differentiation.
Derivative Formulas in Calculus
The three basic derivatives of the algebraic, logarithmic / exponential and trigonometric functions are derived from the first principle of differentiation and are used as standard derivative formulas. They are as follows.
Power Rule of Derivatives
By using the above example, the derivative of x^{2} is 2x. Similarly, we can prove that the derivative of x^{3} is 3x^{2}, the derivative of x^{4} is 4x^{3}, and so on. Power rule generalizes this and it is stated as d/dx (x^{n}) = n x^{n  1}.
Derivatives of Log/Exponential Functions
 The derivative of ln x is, d/dx (ln x) = 1/x
 The derivative of log x is, d/dx (log_{a} x) = 1/(x ln a)
 The derivative of e^x is, d/dx (e^{x}) = e^{x}
 The derivative of a^x is, d/dx (a^{x}) = a^{x} ln a
Derivatives of Trigonometric Functions
Here are the derivatives of trigonometric functions.
 If y = sin x, y' = cos x
 If y = cos x, y' = sin x
 If y = tan x, y' = sec^{2} x
 If y = cot x, y' = cosec^{2} x
 If y = sec x, y' = sec x tan x
 If y = cosec x, y' = cosec x cot x
Derivatives of Inverse Trigonometric Functions
Here are the derivatives of inverse trigonometric functions.
 The derivative of inverse sine is, d/dx (sin^{1}x) = 1/√(1x^{2})
 The derivative of inverse cosine is, d/dx (cos^{1}x) = 1/√(1x^{2})
 The derivative of inverse tan is, d/dx (tan^{1}x) = 1/(1 + x^{2})
 The derivative of inverse cot is, d/dx (cot^{1}x) = 1/(1 + x^{2})
 The derivative of inverse cosec is, d/dx (csc^{1}x) = 1/ [x √(x^{2 } 1) ], x ≠ 1, 1, 0
 The derivative of inverse sec is, d/dx (sec^{1}x) = 1/ [x √(x^{2 } 1) ], x ≠ 1, 1, 0
Fundamental Rules of Derivatives
The following are the fundamental rules of derivatives. Let us discuss them in detail.
Power Rule: By this rule, if y = x^{n }, then dy/dx = n x ^{n1 }. Example: d/dx (x^{5}) = 5x^{4}.
Sum/Difference Rule: The derivative process can be distributed over addition/subtraction. i.e., dy/dx [u ± v]= du/dx ± dv/dx.
Product Rule: The product rule of derivatives states that if a function is a product of two functions, then its derivative is the derivative of the second function multiplied by the first function added to the derivative of the first function multiplied by the second function. dy/dx [u × v] = u · dv/dx + v · du/dx. If y = x^{5 }e^{x }, we have y' = x^{5 }. e^{x }+ e^{x }. 5x^{4 }= e^{x }(x^{5 }+ 5x^{4})
Quotient Rule: The quotient rule of derivatives states that d/dx (u/v) = (v · du/dx  u · dv/dx)/ v^{2 }
Constant multiple Rule: The constant multiple rule of derivatives states that d/dx [c(f(x)] = c · d/dx f(x). i.e., the constant which when multiplied by a function, comes out of the differentiation process. For example, d/dx (5x^{2}) = 5 d/dx (x^{2}) = 5(2x) = 10 x.
Constant Rule: The constant rule of derivatives states that the derivative of any constant is 0. If y = k, where k is a constant, then dy/dx = 0. Suppose y = 4, y' = 0. This rule directly follows from the power rule.
Derivatives of Composite Functions (Chain Rule)
If f and g are differentiable functions in their domain, then f(g(x)) is also differentiable. This is known as the chain rule of differentiation used for composite functions. (fog)'(x) = f'[(g(x)] g'(x). This also can be written as "if y = f(u) and u = g(x) , then dy/dx = dy/du · du/dx.
For example, consider y = tan^{2}x. This is a composite function. We can write this function as y = u^{2}, where u = tan x. Then
dy/du = 2u
du/dx = d/dx (tan x) = sec^{2}x
By the chain rule,
dy/dx = dy/du · du/dx
= 2u · sec^{2}x
= 2 tan x sec ^{2} x
Derivatives of Implicit Functions
In equations where y as a function of x cannot be explicitly defined by the variables x and y, we use implicit differentiation. If f(x, y) = 0, then differentiate on both sides with respect to x and group the terms containing dy/dx at one side, and then solve for dy/dx.
For example, 2x + y = 12
d/dx(2x + y) = d/dx(0)
2 + dy/dx = 0
dy/dx = 2
Parametric Derivatives
In a function, we may have the dependent variables x and y which are dependent on the third independent variable. If x = f(t) and y = g(t), then derivative is calculated as dy/dx = f'(x)/g'(x). Suppose, if x = 4 + t^{2 }and y = 4t^{2 }5t^{4 }, then we find dy/dx as follows.
dx/ dt = 2t and dy/dt = 8t 20t^{3}
dy/dx = (dy/dt)/(dx/dt)
dy/dx = (8t 20t^{3 })/2t
= 2t (4  10t^{2 }) / 2t
dy/dx = 4  10t^{2}
Higherorder Derivatives
We can find the successive derivatives of a function and obtain the higherorder derivatives. If y is a function, then its first derivative is dy/dx. The second derivative is d/dx (dy/dx) which also can be written as d^{2}y/dx^{2}. The third derivative is d/dx (d^{2}y/dx^{2}) and is denoted by d^{3}y/dx^{3} and so on.
Alternatively, the first, second, and third derivatives of f(x) can be written as f'(x), f''(x), and f'''(x). For higher order derivatives, we write the number in brackets as the exponent. Suppose y = 4x^{3}, we get the successive derivatives as follows. y' = 12x^{2} , y'' = 24 x and y''' = 24, y^{(4)}= 0.
Partial Derivatives
If u = f(x,y) we can find the partial derivative of with respect to y by keeping x as the constant or we can find the partial derivative with respect to x by keeping y as the constant. Suppose f(x, y) = x^{3 }y^{2 }, the partial derivatives of the function are:
 ∂f/∂x(x^{3 }y^{2}) = 3x^{2}y and
 ∂f/∂y(x^{3 }y^{2}) = x^{3 }2y
Further, we can find the secondorder partial derivatives also like ∂^{2}f/∂x^{2}, ∂^{2}f/∂y^{2}, ∂^{2}f/∂x ∂y, and ∂^{2}f/∂y ∂x.
Finding Derivative Using Logarithmic Differentiation
Sometimes, the functions are too complex to find the derivatives (or) one function might be raised to another function like y = f(x)^{g(x)}. In such cases, we can take log (or) ln on both sides, apply log rules, and then differentiate on both sides to get dy/dx. This process is known as logarithmic differentiation in calculus.
Example: Find the derivative of y = x^{x}.
Solution:
Applying ln on both sides,
ln y = ln x^{x}
ln y = x ln x
Taking derivative on both sides,
1/y dy/dx = x (1/x) + ln x (1) (by chain rule on left side and product rule on right side)
1/y dy/dx = 1 + ln x
dy/dx = y (1 + ln x) = x^{x} (1 + ln x)
Maxima/Minima by Using Derivatives
The concept of slope, and hence the derivatives, is used to find the maximum or minimum value of a function. There are two tests that use derivatives and are used to find the maxima/minima of a function. They are
First Derivative Test
We can just use the first derivative to determine the maximum or minimum by observing the following points:
 f'(x) represents the slope of a tangent line.
 Hence, if f'(x) > 0, the function is increasing, and if f'(x) < 0, the function is decreasing.
 If f'(x) > 0 is changing to f'(x) < 0 at a point, then the function has a local maximum at that point.
 If f'(x) < 0 is changing to f'(x) > 0 at a point, then the function has a minimum at that point.
 Note that f'(x) = 0 at local maximum and local minimum.
Second Derivative Test
The second derivative test uses the critical points and the second derivative to find the maxima/minima. To perform this test:
 Find the critical points by setting f'(x) = 0.
 Substitute each of these in f''(x). If f''(x) < 0, then the function is maximum at that point and if f''(x)>0, then the function is minimum at that point.
 If f''(x) = 0, the function neither has maxima nor minima at that point, and in this case, it is known as the point of inflection.
Important Notes on Derivatives Calculus:
 A derivative of a function is the rate of change of one quantity over the other.
 Derivative of any continuous function that is differentiable on an interval [a, b] is derived using the first principle of differentiation using the limits.
 If f(x) is given, then its derivative is, f'(x) = lim_{h→0 }[f(x + h)  f(x) / h.
 Every differentiable function is continuous but the converse may not be true.
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Examples of Derivatives

Example 1. Find the derivative of the curve y = [(x+3) (x+2)]/x^{2} at the point (3,0).
Solution:
y = (x^{2 }+ 5x +6)/ x^{2 }= 1 + 5/x + 6/x^{2}
The derivative of the curve is dy/dx = d/dx (1) + d/dx (5/x) + d/dx (6/x^{2})
dy/dx = d/dx (1) + 5 d/dx (x ^{1})^{ }+ 6 d/dx (x^{2})^{ }
= 0 + 5 (1 · x ^{2 }) + 6 (2 · x^{}^{3 }) (Using the power rule of derivatives)
=  5/x^{2 }12/x^{3}
The derivative of the curve at x = 3 is
dy/dx =  5/3^{2 }12/3^{3 }
=  5/9  12 / 27
= 27/27 = 1.
Answer: The derivative y = [(x+3) (x+2)]/x^{2} at the point (3,0) is 1.

Example 2. Suppose the position of an object after t hours is given by g(x) = x/(x+1), then determine if the object is moving to the right or left at t = 10 hours.
Solution:
The derivative of the given function is g'(x) = d/dt . [x/(x+1)]
[(x+1) d/dx(x) x d/dx (x+1)] / (x+1)^{2 }[Applying the quotient rule of derivatives]
= [(x+1) (1)  x(1+0)] / (x+1) ^{2}
Thus g'(x) = 1/(x+1)^{2 }
To determine if the object is moving to the right or left, we need to find the derivative at t = 10.
g'(10) = 1 / 11^{2 }= 1/121
Since the velocity is positive, the object is moving to the right side.
Answer: To the right side.

Example 3. What is the equation of the tangent line to f(x) = x^{2 }+ 5x at x = 4?
Solution:
Given f(x) = x^{2 }+ 5x
f(4) = 4^{2 }+ 5(4)= 16 + 20 = 36
The derivative of f(x) at the given point is the slope of the tangent line.
f'(x) = d/dx (x^{2 }+ 5x ) = 2x + 5
f'(4) = 2(4) + 5 = 13
m = 13
Thus the equation of the tangent at (4, 36) is given by the slope formula: y y_{1} = m (x  x_{1})
y 36 = 13(x  4)
y  36 = 13x  52
y = 13x  52 + 36
y = 13x 16
Answer: The equation of the tangent line to f(x) = x^{2} + 5x at x = 4 is y = 13x 16
FAQs on Derivatives
What are Derivatives in Calculus?
A derivative in calculus is the instantaneous rate of change of a function with respect to another variable. Differentiation is the process of finding the derivative of a function. The derivative of a function is same as the slope of the tangent, rate of change, etc.
Define Derivative.
A derivative of f(x) at x = a is given by f'(x) = lim_{h→0 }[f(x + h)  f(x)] / h. It is the slope of the tangent to the function f(x). In this formula, [f(x + h)  f(x)] / h is known as the difference quotient.
How Do You Find Derivatives?
The derivatives of functions in math are found using the definition of derivative from the first fundamental principle of differentiation. If f(x) is a given function, its derivative is obtained using f'(x) = lim_{h→0 }[f(x + h)  f(x)] / h. A lot of rules are derived by using this limit definition which can be directly used to find the derivatives without using the limits.
What are Basic Derivative Formulas?
The basic derivative formulas are, d/dx (x^{n}) = nx^{n1}, d/dx (ln x) = 1/x, d/dx (e^{x}) = e^{x}, d/dx (a^{x}) = a^{x} ln a, d/dx (sin x) = cos x, d/dx (cos x) =  sin x, d/dx (tan x) = sec^{2}x.
Are Calculus Derivatives Hard?
The process of finding the derivatives using a limit definition is a bit hard. To make this easier, we use the rules that are derived by using the formula. As long as we are able to remember the rules, the process of finding derivatives in calculus is so easy just with a little practice.
What Are the Application of Derivatives in Real Life?
There are various applications of derivatives in real life. The rate of change of a function with respect to another quantity is the derivative. To check if a function is increasing or decreasing, to find the equation of the tangent/normal, to find the maximum and minimum values from a graph, to find the displacementmotion problems, to find velocity given displacement, to find the acceleration given displacement and so on.
What is a Derivative Example?
Speed is the instant rate of change of the distance taken by an object at a particular time. The first derivative of the displacement of an object is its velocity. The second derivative of displacement is the object's acceleration. The third derivative of the displacement is the object's jerk and so on.
What is the Difference Between Derivatives and Differentiation in Calculus?
The derivative of a function f(x) at a point is nothing but the slope of the tangent of the function at that point and is found by the limit f'(x) = lim_{h→0 }[f(x + h)  f(x)] / h. The differentiation is the process of finding the derivatives.
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