# Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°

**Solution:**

We use the basic trigonometric identities and rules of sin and cos to solve the given questions.

cos (90° - θ) = sin θ

Given that: sin 67° + cos 75° ….(i)

Since cos (90° - θ) = sin θ

By using property in equation (i) we get

sin 67° + cos 75° = sin (90° - 23°) + cos (90° - 15°)

= cos 23° + sin 15°

Hence, the expression cos 23° + sin 15° has trigonometric ratios of angles between 0° and 45°.

**Video Solution:**

## Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°

### Maths NCERT Solutions Class 10 - Chapter 8 Exercise 8.3 Question 7:

Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°

sin 67° + cos 75° can be expressed as cos 23° + sin 15° in terms of trigonometric ratios of angles between 0° and 45°