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# Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°

**Solution:**

We will be using the trigonometric ratios of complementary angles to solve the given question.

cos (90° - θ) = sin θ

Given that: sin 67° + cos 75° ….(i)

Since cos (90° - θ) = sin θ

By using this property in equation (i) we get,

sin 67° + cos 75° = sin (90° - 23°) + cos (90° - 15°)

= cos 23° + sin 15°

Hence, the expression cos 23° + sin 15° has trigonometric ratios of angles between 0° and 45°.

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 8

**Video Solution:**

## Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°

Maths NCERT Solutions Class 10 Chapter 8 Exercise 8.3 Question 7

**Summary:**

sin 67° + cos 75° can be expressed as cos 23° + sin 15° in terms of trigonometric ratios of angles between 0° and 45°.

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